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Random No not genrated...

jitendrajitendra Posts: 59New Users @
I want to get the random images from array. images get randomly but some same repetitive images get

i tried this one
for (m = 0; m <=29; m++)
		 rnd = arc4random_uniform(arr.count-m)+m;
		NSString *imageName=[FrontsCards objectAtIndex:rnd];
	fullImageName=[NSString stringWithFormat:@"%@",imageName];
        int padding=0;
		CGRect imageViewFrame=CGRectMake(scrollView.frame.size.width*m+padding, scrollView.frame.origin.y, scrollView.frame.size.width-2*padding, scrollView.frame.size.height);
		ImgView=[[UIImageView alloc]initWithFrame:imageViewFrame];
        [ImgView setImage:[UIImage imageNamed:fullImageName]];
        [scrollView addSubview:ImgView];
		[ImgView setAccessibilityIdentifier:[arr objectAtIndex:rnd]];
		// Tap Gesture  //
		UITapGestureRecognizer *doubleTap = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(doubleTapImgView:)];
		doubleTap.numberOfTapsRequired = 2;
		doubleTap.delegate = self;
		[self.ImgView addGestureRecognizer:doubleTap];
		[self.ImgView setImage:[UIImage imageNamed:fullImageName]];
		NSLog(@"full image name %@",fullImageName);
		NSLog(@"Image Name = %@", fullImageName);

		[self.ImgView setTag:rnd];
		NSString *imageName1=[FrontsCards objectAtIndex:rnd];
		[tweentyarray addObject:imageName1];
	CGSize scrollViewSize=CGSizeMake(scrollView.frame.size.width*30, scrollView.frame.size.height);
	[scrollView setContentSize:scrollViewSize];
	[self.view addSubview:scrollView];

help me out this thanks in advance.



  • Duncan CDuncan C Posts: 9,116Tutorial Authors, Registered Users @ @ @ @ @ @ @
    random does not mean random, non-repeating.

    If you want random non-repeating, then make a mutable copy of your array. Each time you fetch a random object from the mutable array, remove it from the array. Then when the array is empty, re-fill it with the contents of the original array.
    Duncan C

    Animated GIF created with Face Dancer, available for free in the app store.

    I'm available for one-on-one help at CodeMentor
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